Seventh seed Kei Nishikori was eliminated in the third round of the US Open on Friday. The Japanese player, finalist of the same tournament in 2014, was dominated by Australian Alex De Minaur (6-2, 6-4, 2-6, 6-3), 20 years and 38th worldwide. He will not see the quarterfinals, he who had reached this level of competition at the Australian Open, Roland Garros and Wimbledon this season.
Nishikori was picked cold in the first set, releasing three times his service, to find himself led 3-0. Distanced in the next set, he managed to come back to 4-4, before suffering a new break and then losing the set.
Kei Nishikori relaunched in the third inning, leading widely and concluding on a break. But Alex De Minaur finally made the difference in the fourth and final set. After first balanced exchanges, the Australian has signed two breaks, at 3-3 then 5-3, to qualify.
In the round of 16, De Minaur will face Grigor Dimitrov or the lucky loser Polish Kamil Majchrzak, who play Friday night.